C++ threadLocal

最新推荐文章于 2025-09-16 10:02:56 发布

原创最新推荐文章于 2025-09-16 10:02:56 发布 · 512 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#c++ #算法

C++ 专栏收录该内容

61 篇文章

订阅专栏

这篇博客探讨了在线程编程中如何使用线程局部存储(thread_local)来维持每个线程特有的变量，并通过互斥锁(mutex)确保并发访问的安全。示例展示了如何在类A中利用线程局部存储实现线程安全的计数，并在不同线程间调用A的成员函数。此外，还通过示例函数increaseAge展示了线程间的共享状态更新。

#include "iostream"
#include <string>
#include <thread>
#include <mutex>

//using namespace std;

thread_local int age = 1;
std::mutex coutMutex;

void increaseAge(const std::string& threaName)
{
    ++age;
    std::lock_guard<std::mutex> lock(coutMutex);
    std::cout << "increaseAge for " << threaName << ": " <<age <<std::endl;
}

class A
{
    public:
    A() =default;
    ~A() = default;

    void threadLocalTest(const std::string& name)
    {
        thread_local int count = 0;
        ++count;
        std::cout << name << ": " << count << std::endl;
    }

};

void TLTest(const std::string& name)
{
    A a1;
    a1.threadLocalTest(name);
    a1.threadLocalTest(name);


    A a2;
    a2.threadLocalTest(name);
    a2.threadLocalTest(name);
}


int main()
{
    std::thread A(increaseAge, "A");
    std::thread B(increaseAge, "B");

    A.join();
    B.join();

    {
        std::lock_guard<std::mutex> lock(coutMutex);
        std::cout << "increaseAge for main" << ": " <<age << std::endl;
    }

    std::thread t1(TLTest, "t1");
    t1.join();
    std::thread t2(TLTest, "t2");
    t2.join();

    getchar();
    return 0;
}