将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
示例:
输入:1->2->4, 1->3->4 输出:1->1->2->3->4->4
这道题思路比较简单,重点是熟悉链表的基本用法
/**
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} l1
* @param {ListNode} l2
* @return {ListNode}
*/
var mergeTwoLists = function(l1, l2) {
if (l1 === null) return l2;
if (l2 === null) return l1;
var head = null;
var cur = null;
while (l1 !== null || l2 !== null){
if(l1 === null){
cur = cut(cur, l2);
return head || cur;
}
else if (l2 === null){
cur = cut(cur,l1);
return head||cur;
}
else{
if (l1.val<l2.val){
if(cur === null){
head = l1;
cur = head;
}
else{
cur.next = l1;
cur = l1;
}
l1 = l1.next;
}
else{
if (cur === null){
head = l2;
cur = head;
}
else{
cur.next = l2;
cur = l2;
}
l2 = l2.next;
}
}
}
return head;
};
function cut(merged,l){
if (merged === null) return l;
else{
merged.next = l;
return merged;
}
}