Python 日期处理

下面的代码是根据业务需求整理的几个处理日期的方法。

import datetime


class DateTime(object):
    def __init__(self, input_date):
        self.input_date = input_date

    # input_date 的前一天
    # 例如：输入的input_date = datetime.datetime(2018, 1, 17)，输出的结果为20180116
    def getYesterday(self):
        date = self.input_date - datetime.timedelta(days=1)
        yesterday = date.strftime('%Y%m%d')
        #print(yesterday)
        return yesterday

    # input_date 的年月
    # 例如：输入的input_date = datetime.datetime(2018, 1, 17)，输出的结果为201801
    def getMonth(self):
        month = self.input_date.strftime('%Y%m')
        #print(month)
        return month

    # input_date 的上个月
    # 例如，输入的input_date = datetime.datetime(2018, 1, 17)，输出结果为201712
    def getLastMonth(self):
        month = self.input_date.month
        year = self.input_date.year
        if(month == 1):
            month = 12
            year = year - 1
        else:
            month = month - 1
        day = datetime.datetime(year, month, 1)
        last_month = day.strftime('%Y%m')
        #print(last_month)
        return last_month

    # input_date 的本月的第一天
    # 例如：输入的input_date = datetime.datetime(2018, 1, 17)，输出的结果为20180101
    def getMonth1stday(self):
        month = self.input_date.month
        year = self.input_date.year
        month1stday = datetime.datetime(year, month, 1)
        month1stday = month1stday.strftime('%Y%m%d')
        #print(month1stday)
        return month1stday

    # input_date 的当月的第N天
    # 例如：输入的input_date = datetime.datetime(2018, 1, 17)，n = 3, 输出的结果为20171203
    def getMonthNday(self, n):
        month = self.input_date.month
        year = self.input_date.year
        monthNday = datetime.datetime(year, month, 1)
        monthNday = monthNday + datetime.timedelta(days=(n-1))
        monthNday = monthNday.strftime('%Y%m%d')
        #print(monthNday)
        return monthNday


    # input_date 的上月的第N天
    # 例如：输入的input_date = datetime.datetime(2018, 1, 17)，输出结果为20180101
    def getLastMonthNday(self, n):
        month = self.input_date.month
        year = self.input_date.year
        if(month == 1):
            month = 12
            year = year - 1
        else:
            month = month - 1
        lastMonthNday = datetime.datetime(year, month, 1)
        lastMonthNday = lastMonthNday + datetime.timedelta(days=(n-1))
        lastMonthNday = lastMonthNday.strftime('%Y%m%d')
        #print(lastMonthNday)
        return lastMonthNday

    # 如果input_date的天的数字大于等于输入的n，则输出input_date的年月和n日.如果input_date的天的数字小于输入的n，则输出input_date的上个月和n日
    # 例如：我们输入input_date = datetime.datetime(2018, 1, 17)，n = 12, 则输出结果为20180112
    # 我们如果输入input_date = datetime.datetime(2018, 1, 17), n = 22, 则输出结果为20171222
    def getAccountday(self, n):
        month = self.input_date.month
        year = self.input_date.year
        today_day = self.input_date.day
        #today = datetime.datetime.today()
        #today_day = today.day
        if(today_day >= n):
            accountday = datetime.datetime(year, month, 1)
            accountday = accountday + datetime.timedelta(days=(n-1))
            accountday = accountday.strftime('%Y%m%d')
        else:
            if(month == 1):
                month = 12
                year = year - 1
            else:
                month = month - 1
            accountday = datetime.datetime(year, month, 1)
            accountday = accountday + datetime.timedelta(days=(n-1))
            accountday = accountday.strftime('%Y%m%d')
        #print(accountday)
        return accountday

    # 如果input_date的天的数字小于等于输入的n，则输出input_date的前一天；如果input_date的天的数字小于n，则输出input_date的年月和n-1日。
    # 例如：我们输入input_date = datetime.datetime(2018, 1, 17)，n = 12, 则输出结果为20180111
    # 我们如果输入input_date = datetime.datetime(2018, 1, 17), n = 22, 则输出结果为20180116
    def getLastDLday(self, n):
        month = self.input_date.month
        year = self.input_date.year
        #today = datetime.datetime.today()
        today_day = self.input_date.day
        if(today_day <= n):
            lastDLday = self.getYesterday()
        else:
            lastDL1stday = datetime.datetime(year, month, 1)
            lastDLday = lastDL1stday + datetime.timedelta(days=(n-2))
            lastDLday = lastDLday.strftime('%Y%m%d')
        #print(lastDLday)
        return lastDLday

    # 如果input_date的天数-1等于n，则输出input_date的年月和n-1日；如果input_date的天数不等于n，则输出input_date的前一天
    # 例如：输入input_date = datetime.datetime(2018, 1, 13)，n = 12, 则输出20180111
    # 输入的input_date = datetime.datetime(2018, 1, 16), n = 22, 则输出20180115
    def getDLday(self, n):
        month = self.input_date.month
        year = self.input_date.year
        today_day = self.input_date.day
        if((today_day - 1) == n):
            DL1stday = datetime.datetime(year, month, 1)
            DLday = DL1stday + datetime.timedelta(days=(n-2))
            DLday = DLday.strftime('%Y%m%d')
        else:
            DLday = self.getYesterday()
        #print(DLday)
        return DLday


if __name__ == '__main__':
    input_date = datetime.datetime(2018, 1, 17)
    date = DateTime(input_date)
    date.getLastMonthNday(12)
    date.getLastMonth()
    date.getMonth1stday()
    date.getAccountday(12)
    date.getMonthNday(12)
    date.getLastMonthNday(3)
    date.getYesterday()
    date.getDLday(22)
    date.getLastDLday(22)

后续更新中。。。。