节日

//只有90分   目前还未找到错哪了

#include <iostream>
#include <string>
#include <vector>
#include <map>
#include <cstdio>
#include <sstream>
using namespace std;
int mon[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
int isleapyear(int a) {
	return(a%400==0 || (a%4==0 && a%100!=0)) ? 1 :0;
}

int main() {
	int m, w, d, y1, y2;
	
	cin >> m >> w >> d >> y1 >> y2;
	for(int y=y1; y<=y2; y++) {
	int days = 0;
		for(int i=1850; i<y; i++) {
			days += (365+isleapyear(i));
		}
		for(int i=1; i<m; i++) {
			if(i == 2) {
				days += (mon[2]+isleapyear(y));
			} else days += mon[i];
		}
//		cout << days << endl;
		days = (days%7)+2;//月初是周几 
		days = days>7? days-7 : days;
		
		int ans = (d-days+7)%7+(w-1)*7+1;//+1是为了从1.1开始 

		if(ans > mon[m]) {
			printf("none\n");
		} else printf("%d/%02d/%02d\n", y, m, ans);
	}

	return 0;
}