UVa - 10763 Foreign Exchange

本文介绍了一种针对大量学生参与的国际交换项目的配对算法。该算法旨在为每位希望从地点A前往地点B的学生找到一位希望从地点B返回地点A的伙伴。随着参与者数量的增加,使用结构体和排序技巧优化了配对过程。

Problem E
Foreign Exchange
Input:
 standard input
Output: standard output
Time Limit: 1 second

Your non-profit organization (iCORE - international Confederation of Revolver Enthusiasts) coordinates a very successful foreign student exchange program. Over the last few years, demand has sky-rocketed and now you need assistance with your task.

The program your organization runs works as follows: All candidates are asked for their original location and the location they would like to go to. The program works out only if every student has a suitable exchange partner. In other words, if a student wants to go from A to B, there must be another student who wants to go from B to A. This was an easy task when there were only about 50 candidates, however now there are up to 500000 candidates!

Input

The input file contains multiple cases. Each test case will consist of a line containing n - the number of candidates (1≤n≤500000), followed by nlines representing the exchange information for each candidate. Each of these lines will contain 2 integers, separated by a single space, representing the candidate's original location and the candidate's target location respectively. Locations will be represented by nonnegative integer numbers. You may assume that no candidate will have his or her original location being the same as his or her target location as this would fall into the domestic exchange program. The input is terminated by a case where n = 0; this case should not be processed.

 

Output

For each test case, print "YES" on a single line if there is a way for the exchange program to work out, otherwise print "NO".

 

Sample Input                               Output for Sample Input

10

1 2

2 1

3 4

4 3

100 200

200 100

57 2

2 57

1 2

2 1

10

1 2

3 4

5 6

7 8

9 10

11 12

13 14

15 16

17 18

19 20

0

 

YES

NO


刚开始想用map来着 后来想起有重复的 又想用multimap 越改越乱 = = 最后发现自己想多了 刚开始没用结构体 是怕有限制 其实用结构体完全可以解决...排序 查找

刚刚看到一份有bug的代码 是用两个数组储存A,B,排序 判断同一位置的元素是否相同,虽然有bug,但也让我感觉我对排序的巧妙应用确实想得少了点,有时候排序在查找能方便的解决很多问题。

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