HttpClient NameValuePair HttpPost JSONObject 发送请求数据

最新推荐文章于 2025-07-01 11:14:23 发布

JesseCary

最新推荐文章于 2025-07-01 11:14:23 发布

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本文链接：https://blog.youkuaiyun.com/JesseCary/article/details/80229782

该篇博客介绍了如何使用Apache HttpClient库通过HttpPost方法发送带有NameValuePair和JSONObject的HTTP请求。示例代码展示了如何构造请求参数，包括创建NameValuePair、使用UrlEncodedFormEntity编码参数，并通过DefaultHttpClient执行POST请求。

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import net.sf.json.JSONObject;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;

public class HttpTests {

/**
* @param args
* @throws Exception
*/
public static void main(String[] args) throws Exception {
String param1="zhongup";
HttpClient httpclient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost("******/abc");
List<NameValuePair> formParams = new ArrayList<NameValuePair>();
formParams.add(new BasicNameValuePair("param1", param1));
formParams.add(new BasicNameValuePair("param2", "value2"));
HttpEntity entity = new UrlEncodedFormEntity(formParams, "UTF-8");
httpPost.setEntity(entity);
httpclient.execute(httpPost);
httpclient.getConnectionManager().shutdown();
}

}

二

import java.io.IOException;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

import javax.xml.rpc.ServiceException;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.HttpClients;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.util.EntityUtils;

import net.sf.json.JSONObject;

public class Test3 {
public static void main(String[] args) throws ServiceException, ClientProtocolException, IOException {
HttpClient hc=HttpClients.createDefault();
HttpPost post=new HttpPost("http://62.xx.xx.122:9xx0/TaxHttpService/tax_getInfo");
Map map=new HashMap();
map.put("infoKind",2);
String params=JSONObject.fromObject(map).toString();

List<BasicNameValuePair> param=new ArrayList<BasicNameValuePair>();
param.add(new BasicNameValuePair("inputJson", params));
//HttpEntity hh=new StringEntity(params,"UTF-8");
UrlEncodedFormEntity he=new UrlEncodedFormEntity(param,"UTF-8");
post.setEntity(he);
HttpResponse res=hc.execute(post);
HttpEntity entity=res.getEntity();
String msg=EntityUtils.toString(entity,"UTF-8");
System.out.println(msg);
}
}
传递简单{'a':{'c':'d'}}形式的json数据，只能用上面的转换来转换去才成功调通，

这里要记一下EntityUtils和UrlEncodedFormEntity类，一个转换HttpEntity为字符串，一个是对HttpEntity先转换成UTF-8，然后再用URLEncoder转码
下面构造的数据不能用Map存储键值再转换成JSON，暂时并不知道为什么，可能是对方接口解析接收参数的问题，所以弄得很古灵精怪的，用下面的方法才接通。

构造的数据是:

[inputJson={"infoKind":2,"cName":"fsdfs","taxRate":17,"invoicer":"zzzzz","sAddress":"ddddddddddd","sBank":"ddddddddddd","details":[{"amount":88.12,"goodsName":"asdaas","priceKind":0,"taxRate":17}]}]

import java.io.IOException;
import java.util.ArrayList;
import java.util.List;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.HttpClients;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.util.EntityUtils;

import net.sf.json.JSONArray;
import net.sf.json.JSONObject;

public class Test4 {

public static void main(String[] args) throws ClientProtocolException, IOException {
// TODO Auto-generated method stub
new Test4().test();
}
public String invoice(){
JSONObject obj=new JSONObject();
obj.put("infoKind", 2);
obj.put("cName", "fsdfs");
obj.put("taxRate", 17);
obj.put("invoicer", "zzzzz");
obj.put("sAddress", "ddddddddddd");
obj.put("sBank", "ddddddddddd");
////////////////////////////////
JSONArray arr=new JSONArray();
JSONObject d=new JSONObject();
d.put("amount", 88.12);
d.put("goodsName", "asdaas");
d.put("priceKind", 0);
d.put("taxRate", 17);
d.put("goodsTaxNo", "10101013301");
d.put("taxPre", 0);
d.put("taxPreCon", "免税");
d.put("goodsNoVer", "1.0");
////////////////////////////////
//String jsonstr=d.toString();
arr.add(d);
obj.put("details", arr);
System.out.println(obj.toString());
return obj.toString();
}
public void test() throws ClientProtocolException, IOException{
HttpClient hc=HttpClients.createDefault();
HttpPost post=new HttpPost("http://11.11.11.11xxxx");
List<BasicNameValuePair> nv=new ArrayList<BasicNameValuePair>();
nv.add(new BasicNameValuePair("inputJson", invoice()));
UrlEncodedFormEntity he=new UrlEncodedFormEntity(nv,"utf-8");
post.setEntity(he);
HttpResponse res=hc.execute(post);
HttpEntity entity=res.getEntity();
String msg=EntityUtils.toString(entity,"UTF-8");
System.out.println(">>>>>>>>>>>>>>>>>"+msg);
}
}
总结：对接别人的接口时，切记要问清楚传递参数的格式，这里对方的参数格式是inputJson={'a':'c'}

下面构造的数据不能用Map存储键值再转换成JSON，暂时并不知道为什么，可能是对方接口解析接收参数的问题，所以弄得很古灵精怪的，用下面的方法才接通。

构造的数据是:

[inputJson={"infoKind":2,"cName":"fsdfs","taxRate":17,"invoicer":"zzzzz","sAddress":"ddddddddddd","sBank":"ddddddddddd","details":[{"amount":88.12,"goodsName":"asdaas","priceKind":0,"taxRate":17}]}]