需求
看一个具体的需求
看一个披萨的项目:要便于披萨种类的扩展,要便于维护1)
1)披萨的种类很多(比如GreekPizz、CheesePizz等)
2)披萨的制作有prepare,bake, cut,box
3)完成披萨店订购功能。
详解图
披萨类
public abstract class Pizza {
protected String name; //名字
//准备原材料,不同的披萨不一样因此,我们做成抽象方法
public abstract void prepare();
public void bake() {
System.out.print1n(name + " baking; ");
}
public void cut() {
System.out.println(name + " cutting; ");
}
//打包
public void box() {
System.out.print1n(name + " boxing; ");
}
public void setName(String name) {
this.name = name;
}
}
各类披萨
public class CheesePizza extends Pizza {
@Override
public void prepare() {
System.out.println("给制作奶酪披萨准备原材料");
}
}
public class GreekPizza extends Pizza {
@override
public void prepare() {
System.out.println("给希腊披萨准备原材料");
}
}
订购披萨
public OrderPizza(){
Pizza pizza = null;
String orderType; //订购披萨的类型
do {
orderType = getType();
if (orderType.equals( "greek")) {
pizza = new GreekPizza();pizza.setName("希腊披萨");
}else if (orderType.equals("cheese")){
pizza = new CheesePizza();
pizza.setName("奶酷披萨");
}else {
break;
}
//输出pizza制作过程
pizza.prepare();
pizza.bake();
pizza.cut();
pizza.box();
}while (true);
}
//写一个方法,可以获取客户希望订购的披萨种类
private String getType() {
try {
BufferedReader strin = new BufferedReader(newInputStreamReader(System.in));
System.out.printLn( "input pizza种类E");
String str = strin.readLine();
return str;
}catch (IOException e) {
e.printStackTrace();
}
return strin;
}
}
客户端订购披萨
//相当于一个客户端,发出订购
public class PizzaStore {
public static void main(String[] args) {
new OrderPizza();
}
}