1. Use fori iterate, get the index
2. current index has to less than list size minus one
For example:
[1,2,3,4,5] size is 5
Index (4) is the last element, which is 5
So index number has to be less than 4, which is the (size -1)
if (deviceInfos.size() -1 > i2) {
double lngtd1 = Double.parseDouble(deviceInfos.get(i2).getLngtd());
double lngtd2 = Double.parseDouble(deviceInfos.get(i2 + 1).getLngtd());
double lattd1 = Double.parseDouble(deviceInfos.get(i2).getLattd());
double lattd2 = Double.parseDouble(deviceInfos.get(i2 + 1).getLattd());
double distance = DistanceUtils.getDistance(lngtd1, lattd1, lngtd2, lattd2);
json.put("distance", distance+"m");
}else {
json.put("distance","0m");
}
本文介绍了一种使用迭代方法计算列表中连续元素间距离的算法。通过遍历设备信息列表,获取每一对连续位置的经纬度坐标,并计算它们之间的地理距离。
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