根据时间生成10位唯一性编码（最少9位）

最新推荐文章于 2024-07-01 02:54:06 发布

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该代码示例展示了如何利用日期时间（年、月、日、时、分、秒、毫秒）结合随机数生成10位的唯一性编码。首先将时间转换为62进制字符序列，然后添加一个1位的随机密钥，确保编码的唯一性。

private static char[] chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890".ToArray();
public static string CreatCode()
{
int Year = Convert.ToInt32(DateTime.Now.Year.ToString());//2位
int Month = Convert.ToInt32(DateTime.Now.Month.ToString());//1位
int Day = Convert.ToInt32(DateTime.Now.Day.ToString());//1位
int Hour = Convert.ToInt32(DateTime.Now.Hour.ToString());//1位
int Minute = Convert.ToInt32(DateTime.Now.Minute.ToString());//1位
int Second = Convert.ToInt32(DateTime.Now.Second.ToString());//1位
int Millisecond = Convert.ToInt32(DateTime.Now.Millisecond.ToString());//2位
List<int> IntTimes = new List<int>();
IntTimes.Add(Year);
IntTimes.Add(Month);
IntTimes.Add(Day);
IntTimes.Add(Hour);
IntTimes.Add(Minute);
IntTimes.Add(Second);
IntTimes.Add(Millisecond);
string code = TimeToString64(IntTimes) + GetUniqueKey(1);
Thread.Sleep(100);
return code;
}
/// <summary>
/// 将时间转化为对应62位字符序列中的字符编码
/// </summary>
/// <param name="number"></param>
/// <returns></returns>
public static string TimeToString64(List<int> number)
{
int size = 10;
StringBuilder result = new StringBuilder(size);
foreach (int item in number)
{
if (item / 62 == 0)
{
result.Append(chars[item % (chars.Length - 1)]);
}
else
{
result.Append(chars[(item / 62) % (chars.Length - 1)]);
result.Append(chars[item % (chars.Length - 1)]);
}
}
return result.ToString();
}
private static string GetUniqueKey(int size)
{
RNGCryptoServiceProvider crypto = new RNGCryptoServiceProvider();
byte[] data = new byte[size];
crypto.GetNonZeroBytes(data);
StringBuilder result = new StringBuilder(size);
foreach (byte b in data)
{
result.Append(chars[b % (chars.Length - 1)]);
}
return result.ToString();
}