一、Description
You are a sub captain of Caesar's army. It is your job to decipher the messages sent by Caesar and provide to your general. The code is simple. For each letter in a plaintext message, you shift it five places to the right to create the secure message (i.e., if the letter is 'A', the cipher text would be 'F'). Since you are creating plain text out of Caesar's messages, you will do the opposite:
Cipher text
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Plain text
V W X Y Z A B C D E F G H I J K L M N O P Q R S T U
Only letters are shifted in this cipher. Any non-alphabetical character should remain the same, and all alphabetical characters will be upper case.
Input
A single data set has 3 components
- Start line - A single line, "START"
- Cipher message - A single line containing from one to two hundred characters, inclusive, comprising a single message from Caesar
- End line - A single line, "END"
Output
二、问题分析
最近两天,哥们被三伏天折磨的想死的心都有了。于是乎,我决定找几道水题来降降温。这道号称是“史上最难的问题”的题目就是一道标准的水题。
题目很简单,密码转译问题。开始的时候以为是加密,这也算是我所唯一检查了的地方。用字符串存放输入,然后把字符串转换为字符数组。把字母分为两部分,A~F字符转换为Ascii码后加21,G~Z转换为AscII后减5。遍历每个字符,按上面的规则改变字母。
刚刚看到网友爆料,此题居然和3749一样。我还以为是和它一样水呢,没想到是一样的题,不过3749是中文的。哎呀,还省了翻译的时间,要知道水题最难之处就是翻译啊!!!
三、Java代码
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Main {
public static void main(String[] args) throws IOException {
BufferedReader read=new BufferedReader(new InputStreamReader(System.in));
while(!read.readLine().equals("ENDOFINPUT")){
String s=read.readLine();
char[] c=s.toCharArray();
for(int i=0;i<c.length;i++){
int a=(int)c[i];
if(a>= 70 && a<=90){
c[i]=(char) (c[i]-5);
}else if(a>=65 && a<=69){
c[i]=(char) (c[i]+21);
}
}
System.out.println(c);
read.readLine();
}
}
}
1465



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