StrangeClock解析-优快云博客

本文介绍了一个特殊的时钟，该时钟没有数字标记，而是通过时针的角度来确定具体的时间。文章详细解释了如何根据输入的角度判断当前时间，并提供了一个C++程序示例，用于解决这一问题。示例中包括了输入角度的范围、处理逻辑及输出格式。

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Strange Clock

Time Limit: 1 Second Memory Limit: 32768 KB

There is a strange clock, without any number written. Can you tell me what time it is now, based on the angle of the hour hand?

When the hour hand points right (0 degree), it is 3 o'clock. When it points to 80 degrees, it's between 0 o'clock and 1 o'clock. Note that there is no 12 o'clock. You should always write 0 o'clock instead.

Input

There are at most 10 test cases. Each case contains a single integer a (0 <= a < 360), the angle of the hour hand. The input ends with a = -1.

Output

For each test case, print the current time, in one of the following format:

- Exactly x o'clock
- Between x o'clock and y o'clock

Note that, in the second format, x o'clock should be exactly one hour before y o'clock, So you cannot write something like "Between 3 o'clock and 2 o'clock".

Sample Input

90
 245
-1

Sample Output

Exactly 0 o'clock
Between 6 o'clock and 7 o'clock
#include <iostream>
using namespace std;

int main()
{
	int n;
	int c[12] = {90,60,30,0,330,300,270,240,210,180,150,120};
	while(scanf("%d",&n)&&n!=-1)
	{
		if(n>330)
		{
			printf("Between 3 o'clock and 4 o'clock/n");
			continue;
		}
		int i ,t,tt;
		for( i = 0; ; i++)
		{
			t = i%12;
			tt = t+1;
			if(t==11)
				tt = 0;

			if(n==c[t]||(n<c[t]&&n>c[tt]))
				break;
		}
		if(n==c[t])
			printf("Exactly %d o'clock/n",t);
		else
			printf("Between %d o'clock and %d o'clock/n",t,tt);
	}
	return 0;
}

测试数据

zoj 3191