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最新推荐文章于 2018-06-22 23:01:54 发布

Ididcan

最新推荐文章于 2018-06-22 23:01:54 发布

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分类专栏： ACM 文章标签： dataset integer numbers input output each

本文链接：https://blog.youkuaiyun.com/Ididcan/article/details/4632373

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本文介绍了一个计算三角形数加权总和的程序，该程序能够接收一系列正整数作为输入，并输出对应的加权三角数总和。具体而言，对于每一个输入的n，程序会计算从1到n的所有k * T(k+1)之和，其中T(n)为第n个三角形数。

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Triangular Sums

Time Limit: 1 Second Memory Limit: 32768 KB

The nth Triangular number, T(n) = 1 + ... + n, is the sum of the first n integers. It is the number of points in a triangular array with n points on side.

For example T(4):

   X
  X X
 X X X
X X X X

Write a program to compute the weighted sum of triangular numbers:

W(n) = SUM[k = 1..n; k*T(k+1)]

Input

The first line of input contains a single integer N, (1 <= N <= 1000) which is the number of datasets that follow.

Each dataset consists of a single line of input containing a single integer n, (1 <= n <= 300), which is the number of points on a side of the triangle.

Output

For each dataset, output on a single line the dataset number, (1 through N), a blank, the value of n for the dataset, a blank, and the weighted sum , W(n), of triangular numbers for n.

Sample Input

4
3
4
5
10

Sample Output

1 3 45
2 4 105
3 5 210
4 10 2145

//2773 #include <iostream> using namespace std; int main() { int n; cin>>n; int i = 0; while(n--) { int num; cin>>num; i++; long r = 0; //在这里使用int/long/long long 都可以通过 for(int k = 1; k <= num; k++) { r += (k*(k+1)*(k+2)/2); } cout<<i<<" "<<num<<" "<<r<<endl; } return 0; }