C++ 五子棋

最新推荐文章于 2025-11-05 23:28:54 发布

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最新推荐文章于 2025-11-05 23:28:54 发布 · 358 阅读

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本文介绍如何使用C++编程语言实现一个简单的五子棋游戏。内容涵盖棋盘的初始化，玩家轮流落子，判断胜负，以及游戏的回溯算法等关键功能。

//创建对话框，绘制五子棋，并实现五子棋的输赢判断
#include<windows.h>
#include <tchar.h>

//棋盘和棋手，黑子先手
LPCWSTR lps[11] = { L" 1",L" 2",L" 3",L" 4",L" 5",L" 6",L" 7",L" 8",L" 9",L"10",L"11" };
int chessboard[11][11] = {
		0,0,0,0,0,0,0,0,0,0,0,
		0,0,0,0,0,0,0,0,0,0,0,
		0,0,0,0,0,0,0,0,0,0,0,
		0,0,0,0,0,0,0,0,0,0,0,
		0,0,0,0,0,0,0,0,0,0,0,
		0,0,0,0,0,0,0,0,0,0,0,
		0,0,0,0,0,0,0,0,0,0,0,
		0,0,0,0,0,0,0,0,0,0,0,
		0,0,0,0,0,0,0,0,0,0,0,
		0,0,0,0,0,0,0,0,0,0,0,
		0,0,0,0,0,0,0,0,0,0,0
}, chequer = -1;

//重新开始
void reset()
{
	for (int i = 0; i <= 10; i++)
		for (int j = 0; j <= 10; j++)
			chessboard[i][j] = 0;
	chequer = -1;
}
//判断输赢
int judgeWinner()
{
	//横向
	for (int i = 0; i <= 10; i++)
		for (int j = 0; j <= 6; j++)
		{
			if (chessboard[i][j] == 1 && chessboard[i][j + 1] == 1 && chessboard[i][j + 2] == 1 && chessboard[i][j + 3] == 1 && chessboard[i][j + 4] == 1)
				return 1;
			if (chessboard[i][j] == -1 && chessboard[i][j + 1] == -1 && chessboard[i][j + 2] == -1 && chessboard[i][j + 3] == -1 && chessboard[i][j + 4] == -1)
				return -1;
		}
	//纵向
	for (int j = 0; j <= 10; j++)
		for (int i = 0; i <= 6; i++)
		{
			if (chessboard[i][j] == 1 && chessboard[i + 1][j] == 1 && chessboard[i + 2][j] == 1 && chessboard[i + 3][j] == 1 && chessboard[i + 4][j] == 1)
				return 1;
			if (chessboard[i][j] == -1 && chessboard[i + 1][j] == -1 && chessboard[i + 2][j] == -1 && chessboard[i + 3][j] == -1 && chessboard[i + 4][j] == -1)
				return -1;
		}
	//右斜线
	for (int i = 0; i <= 6; i++)
		for (int j = 0; j <= 6; j