Problem 13 大和

1，输入数字，并将数字倒序存储

2，对齐后相加

3，处理进位

4，输出答案

#include <iostream>
#include <cstring>
using namespace std;

char num1[1005], num2[1005];
int n1[1005], n2[1005], ans[1005];

int main() {
	cin >> num1 >> num2;
	n1[0] = strlen(num1);
	n2[0] = strlen(num2);
	ans[0] = max(n1[0], n2[0]);
	for (int i = 1, j = n1[0] - 1; i <= n1[0]; i++, j--) {
		n1[i] = num1[j] - '0';
	}
	for (int i = 1, j = n2[0] - 1; i <= n2[0]; i++, j--) {
		n2[i] = num2[j] - '0';
	}
	for (int i = 1; i <= ans[0]; i++) {
		ans[i] = n1[i] + n2[i];
	}
	for (int i = 1; i <= ans[0]; i++) {
		if (ans[i] > 9) {
			ans[i + 1] += ans[i] / 10;
			ans[i] %= 10;
			if (i == ans[0]) ans[0]++;
		}
	}
	for (int i = ans[0]; i > 0; i--) {
		cout << ans[i];
	}
	cout << endl;

	return 0;
}

输出：

[huochuanfei@localhost alg1]$ ./a.out 
101
999
1100