tiktokOA fizz buzz

自己做的

class Solution {
public:
    vector<string> fizzBuzz(int n) {
        vector<string> res;
        for(int i = 1; i <= n; i++){
            if(i % 3 == 0){
                if(i % 5 == 0){
                    res.push_back("FizzBuzz");
                }
                else{
                    res.push_back("Fizz");
                }
            }
            else if(i % 5 == 0)
                res.push_back("Buzz");
            else{
                string temp = to_string(i);
                res.push_back(temp);
            }
        }
        return res;
    }
};

如果再增加几个整除的数，把Fizzbuzz换成 %30 += Fizz， %50 += Buzz会更简洁

也可以用哈希表存对应的串
So, for FizzBuzzJazz the hash table would look something like { 3: ‘Fizz’, 5: ‘Buzz’, 7: ‘Jazz’ }