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LeetCode:7. Reverse Integer

Given a 32-bit signed integer, reverse digits of an integer.
Example 1:

Input: 123
Output: 321

Example 2:

put: -123
Output: -321

Example 3:

Input: 120
Output: 21

Note:Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

 public  int Reverse(int x)
  {
         int rev = 0;
         while (x != 0)
         {
             int pop = x % 10;
             x /= 10;
             if (rev > int.MaxValue / 10 || (rev == int.MaxValue / 10 && pop > 7)) 
return 0;
             if (rev < int.MinValue / 10 || (rev == int.MinValue / 10 && pop < -8)) 
return 0;
             rev = rev * 10 + pop;
         }
         return rev;
     }
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Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before c

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LeetCode:Reverse Integer - 翻转数字

1、题目名称 Reverse Integer(翻转数字) 2、题目地址 https://leetcode.com/problems/reverse-integer/ 3、题目内容 英文:Reverse digits of an integer. 中文:翻转一个正整数的各位,形成一个...

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