<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title><![CDATA[HenyBadBoy的博客]]></title><description><![CDATA[]]></description><link>https://blog.youkuaiyun.com/HenyBadBoy</link><language>zh-cn</language><generator>https://blog.youkuaiyun.com/</generator><copyright><![CDATA[Copyright &copy; HenyBadBoy]]></copyright><item><title><![CDATA[求解数字和为sum的方法数]]></title><link>https://blog.youkuaiyun.com/HenyBadBoy/article/details/121657765</link><guid>https://blog.youkuaiyun.com/HenyBadBoy/article/details/121657765</guid><author>HenyBadBoy</author><pubDate>Wed, 01 Dec 2021 16:08:50 +0800</pubDate><description><![CDATA[include&lt;stdio.h&gt;
define MAXN 1001
define MAXS 1001
define max(x,y) ((x)&gt;(y)?(x):(y))
int n,sum;
int a[MAXN];
long dp[MAXN][MAXS];
long solve(){
int i, j;
for(i =0; i&lt;n; i++){
dp[i][0] = 1;
}
for(j=1; j&lt;sum; j++){
dp[0][j]=0;
for(i=1; i&lt;=n]]></description><category></category></item><item><title><![CDATA[【无标题】]]></title><link>https://blog.youkuaiyun.com/HenyBadBoy/article/details/121657693</link><guid>https://blog.youkuaiyun.com/HenyBadBoy/article/details/121657693</guid><author>HenyBadBoy</author><pubDate>Wed, 01 Dec 2021 16:06:21 +0800</pubDate><description><![CDATA[include&lt;stdio.h&gt;
define MAXN 1001
define MAXS 1001
define max(x,y) ((x)&gt;(y)?(x):(y))
int n,sum;
int a[MAXN];
long dp[MAXN][MAXS];
long solve(){
int i, j;
for(i =0; i&lt;n; i++){
dp[i][0] = 1;
}
for(j=1; j&lt;sum; j++){
dp[0][j]=0;
for(i=1; i&lt;=n]]></description><category></category></item><item><title><![CDATA[opencv C++ 图像融合下的以 imageROI为例子的image函数的注意事项]]></title><link>https://blog.youkuaiyun.com/HenyBadBoy/article/details/113530755</link><guid>https://blog.youkuaiyun.com/HenyBadBoy/article/details/113530755</guid><author>HenyBadBoy</author><pubDate>Mon, 01 Feb 2021 22:05:01 +0800</pubDate><description><![CDATA[imageROI的注意事项：
imageROI = image(Rect(100, 100, logo.cols, logo.rows));
这里面的两个100是跟 所需要混合的 图片的分辨率有关，
例子：
有两个图像的分辨率为：1. 500 * 500；2. 200 * 200；
这时想把2的图片融合到1的图片所需的函数如下：
imageROI = image(Rect(100, 100, logo.cols, logo.rows));
这个是可以的，即在1的图片100 * 100的位置下放下200*20]]></description><category></category></item></channel></rss>