亚马逊邮件中文乱码问题解决办法

最新推荐文章于 2022-01-06 02:59:20 发布

原创最新推荐文章于 2022-01-06 02:59:20 发布 · 1.5k 阅读

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本文介绍了一种利用Amazon Simple Email Service (SES)通过SMTP协议发送包含HTML内容邮件的方法。文章详细展示了如何设置邮件发送所需的配置参数，如协议、端口、认证方式等，并提供了创建邮件、设置发件人、收件人、主题及内容的具体步骤。

Transport transport = null;
boolean result;
try {
    // Create a Properties object to contain connection configuration information.
    Properties props = System.getProperties();
    props.put("mail.transport.protocol", "smtp");
    props.put("mail.smtp.port", PORT);
    props.put("mail.smtp.starttls.enable", "true");
    props.put("mail.smtp.auth", "true");
    // Create a Session object to represent a mail session with the specified properties.
    Session session = Session.getDefaultInstance(props);
    // Create a message with the specified information.
    MimeMessage msg = new MimeMessage(session);
    msg.setFrom(new InternetAddress(FROM, FROM_NAME));
    msg.setRecipient(Message.RecipientType.TO, new InternetAddress(recipient));
    msg.setSubject(subject);

    //text/html;charset=UTF-8解决中文乱码问题
    msg.setContent(stringBuilder.toString(),"text/html;charset=UTF-8");

    // Add a configuration set header. Comment or delete the
    // next line if you are not using a configuration set
    msg.setHeader("X-SES-CONFIGURATION-SET", CONFIG_SET);

    // Create a transport.
    transport = session.getTransport();

    // Send the message.
    System.out.println("Sending...");
    // Connect to Amazon SES using the SMTP username and password you specifiedabove.
    transport.connect(HOST, SIMPLE_MAIL_TRANSFER_PROTOCOL_NAME, SIMPLE_MAIL_TRANSFER_PROTOCOL_PASSWORD);
    // Send the email.
    transport.sendMessage(msg, msg.getAllRecipients());
    log.info("Email sent!");
    result = true;
} catch (Exception ex) {
    ex.printStackTrace();
    log.info("The email was not sent.");
    log.info("Error message: " + ex.getMessage());
    result = false;
} finally {
    // Close and terminate the connection.
    if (transport != null) {
        try {
            transport.close();
        } catch (MessagingException e) {
            e.printStackTrace();
        }
    }
}