Given a binary tree, return the postorder traversal of its nodes' values.
For example:
Given binary tree {1,#,2,3}
,
1 \ 2 / 3
return [3,2,1]
.
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public List<Integer> postorderTraversal(TreeNode root) {
List<Integer> left;
List<Integer> right;
List<Integer> list = new LinkedList<Integer>();
if(root == null)
return list;
left = postorderTraversal(root.left);
right = postorderTraversal(root.right);
for(int i = 0; i < left.size(); i++)
list.add(left.get(i));
for(int j = 0; j < right.size(); j++)
list.add(right.get(j));
list.add(root.val);
return list;
}
}