Tutor
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others)
Total Submission(s): 1152 Accepted Submission(s): 206
Total Submission(s): 1152 Accepted Submission(s): 206
Problem Description
Lilin was a student of Tonghua Normal University. She is studying at University of Chicago now. Besides studying, she worked as a tutor teaching Chinese to Americans. So, she can earn some money per month. At
the end of the year, Lilin wants to know his average monthly money to decide whether continue or not. But she is not good at calculation, so she ask for your help. Please write a program to help Lilin to calculate the average money her
earned per month.
Input
The first line contain one integer T, means the total number of cases.
Every case will be twelve lines. Each line will contain the money she earned per month. Each number will be positive and displayed to the penny. No dollar sign will be included.
Every case will be twelve lines. Each line will contain the money she earned per month. Each number will be positive and displayed to the penny. No dollar sign will be included.
Output
The output will be a single number, the average of money she earned for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign without tail zero. There will be no other spaces
or characters in the output.
SampleInput
2 100.00 489.12 12454.12 1234.10 823.05 109.20 5.27 1542.25 839.18 83.99 1295.01 1.75 100.00 100.00 100.00 100.00 100.00 100.00 100.00 100.00 100.00 100.00 100.00 100.00
SampleOutput
$1581.42 $100
Code1:
#include <algorithm>
#include <iostream>
#include <cstring>
#include <string>
#include <cstdio>
#include <vector>
#include <queue>
#include <cmath>
#include <map>
#include <set>
#define eps 1e-7
#define LL long long
#define pb push_back
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define Max(a,b) ((a)>(b)?(a):(b))
#define Min(a,b) ((a)<(b)?(a):(b))
using namespace std;
int main()
{
int T;
double mon,f;
scanf("%d",&T);
while(T--){
mon=0.0;
for(int i=0;i<12;i++) {
scanf("%lf",&f);
mon+=f;
}
mon/=12.0;
mon+=0.005; //四舍五入的方法:先加0.005,再乘100,向下取整
LL tmp=(LL)floor((mon*100));
LL x=tmp%10;
LL y=(tmp%100)/10;
cout<<"$"<<tmp/100;
if(x) cout<<"."<<y<<x;
else if(y) cout<<"."<<y;
puts("");
}
}
Code:
#include <algorithm>
#include <iostream>
#include <cstring>
#include <string>
#include <cstdio>
#include <vector>
#include <queue>
#include <cmath>
#include <map>
#include <set>
#define eps 1e-7
#define LL long long
#define pb push_back
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define Max(a,b) ((a)>(b)?(a):(b))
#define Min(a,b) ((a)<(b)?(a):(b))
using namespace std;
double x;
int T;
LL mo;
int main()
{
scanf("%d",&T);
while(T--){
mo=0;
for(int i=0;i<12;i++){
scanf("%lf",&x);
mo=mo+(LL)(x*10000);
}
mo/=12;
LL tmp=mo%100;
if(tmp>=50) mo+=100;
mo/=100;
LL x=mo%10;
LL y=(mo%100)/10;
printf("$%I64d",mo/100);
if(x) {
printf(".%I64d%I64d",y,x);
}
else if(y){
printf(".%I64d",y);
}
puts("");
}
return 0;
}