Python简易猜拳游戏

用户通过输入1/2/3来对应石头剪刀布，界面效果如图所示：

点击4退出游戏后会展示这之前的游戏统计结果，如图所示：

代码如下：

#1、石头，2、剪刀、3布
import random


def translateState(num):
    if (num == 1):
        return '石头'
    elif (num == 2):
        return '剪刀'
    elif (num == 3):
        return '布'


a = 0#玩家胜利次数
b = 0#电脑胜利次数
c = 0#平局次数
print("请输入操作：（1-石头   2-剪刀   3-布    4-退出）")
player = int(input())
while player:
    computer = random.randint(1,3)
    if player not in(1,2,3,4):
        print("您所输入的命令不正确，请重新输入！")
        player = int(input())
    else:
        if player == 4:
            player=0
        else:
            print("玩家输入的是%s,电脑输入的是%s"%(translateState(player),translateState(computer)))
            if ((player == 1 and computer == 2)
                or (player ==2 and computer==3)
                or(player ==3 and computer == 1)):
                print("玩家胜利！")
                a+=1
            elif ((player == 2 and computer == 1)
                or (player ==3 and computer==2)
                or(player ==1 and computer == 3)):
                print("电脑胜利！")
                b+=1
            else:
                print("平局!")
                c+=1
            player = int(input())
print("成功退出游戏！")
print("玩家胜利了%d局"%a)
print("电脑胜利了%d局"%b)
print("平局%d局"%c)