Codeforces Round #240 (Div. 1)B---Mashmokh and ACM(水dp)

这篇博客介绍了一个编程任务,要求找到所有长度为k且每个数字能被下一个数字整除的序列(好序列)。给定整数n和k,求解这类序列的数量,并对10^9 + 7取模。示例给出了不同n和k的解决方案数量。

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Mashmokh’s boss, Bimokh, didn’t like Mashmokh. So he fired him. Mashmokh decided to go to university and participate in ACM instead of finding a new job. He wants to become a member of Bamokh’s team. In order to join he was given some programming tasks and one week to solve them. Mashmokh is not a very experienced programmer. Actually he is not a programmer at all. So he wasn’t able to solve them. That’s why he asked you to help him with these tasks. One of these tasks is the following.

A sequence of l integers b1, b2, …, bl (1 ≤ b1 ≤ b2 ≤ … ≤ bl ≤ n) is called good if each number divides (without a remainder) by the next number in the sequence. More formally for all i (1 ≤ i ≤ l - 1).

Given n and k find the number of good sequences of length k. As the answer can be rather large print it modulo 1000000007 (109 + 7).
Input

The first line of input contains two space-separated integers n, k (1 ≤ n, k ≤ 2000).
Output

Output a single integer — th

Codeforces的动态规划题单中,有基础DP、优化递推式、进阶DP、数据结构、优先队列、并查集、图论、最短路、最小生成树、数论、二分搜索等不同类型的题目。 代码中的内容是一个动态规划的例子,它采用了一个二维数组来存储中间结果,并通过递推的方式计算最优解。这个例子中,它使用了一个for循环嵌套来遍历数组,并利用状态转移方程更新数组中的值。最后输出的是计算得到的最优解。 要注意的是,这段代码是一个完整的程序,需要依赖于一些特定的输入数据才能正确运行。如果你想在Codeforces上找到更多的动态规划题目,可以访问它们的官方网站并浏览题库。<span class="em">1</span><span class="em">2</span><span class="em">3</span> #### 引用[.reference_title] - *1* [牛客练习_21314:codeforces (动态规划+01背包)](https://blog.csdn.net/qq_45750296/article/details/109587967)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v93^chatsearchT3_2"}}] [.reference_item style="max-width: 33.333333333333336%"] - *2* [leetcode双人赛-acm-challenge-workbook:acm-挑战-工作簿](https://download.csdn.net/download/weixin_38701340/19923844)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v93^chatsearchT3_2"}}] [.reference_item style="max-width: 33.333333333333336%"] - *3* [Codeforces Round #750 (Div. 2)E题(动态规划)](https://blog.csdn.net/m0_51506743/article/details/121083708)[target="_blank" data-report-click={"spm":"1018.2226.3001.9630","extra":{"utm_source":"vip_chatgpt_common_search_pc_result","utm_medium":"distribute.pc_search_result.none-task-cask-2~all~insert_cask~default-1-null.142^v93^chatsearchT3_2"}}] [.reference_item style="max-width: 33.333333333333336%"] [ .reference_list ]
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