SDUT2015暑假集训14级周赛1 E - 尤文图斯(NP-博弈)

本文链接：https://blog.youkuaiyun.com/Grit_ICPC/article/details/47188301

本文探讨了一种基于游戏棋盘的胜负策略分析方法。通过分析棋盘游戏的不同状态（N状态与P状态），确定了游戏双方在完美策略下的胜负结果。文章提供了具体的算法实现，并总结出当棋盘行列数均为奇数时为必败状态，其余情况均为必胜状态的规律。

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E - 尤文图斯

Time Limit:1000MS Memory Limit:10000KB 64bit IO Format:%I64d & %I64u

Description

Recently kiki has nothing to do. While she is bored, an idea appears in his mind, she just playes the checkerboard game.The size of the chesserboard is n*m.First of all, a coin is placed in the top right corner(1,m). Each time one people can move the coin into the left, the underneath or the left-underneath blank space.The person who can't make a move will lose the game. kiki plays it with ZZ.The game always starts with kiki. If both play perfectly, who will win the game?

Input

Input contains multiple test cases. Each line contains two integer n, m (0<n,m<=2000). The input is terminated when n=0 and m=0.

Output

If kiki wins the game printf "Wonderful!", else "What a pity!".

Sample Input

Sample Output

     
      What a pity!
Wonderful!
Wonderful!

所谓的NP就是玩家每次走都有两种可能必胜和必败 P->败，N->胜（是指下一个人的状态）。

#include<iostream>
#include<cstring>
#include<cstdio>

using namespace std;

int main()
{
    int n,m,i,j;
    ios::sync_with_stdio(false);
    while(cin>>n>>m&&n&&m)
    {
         if(n%2!=0&&m%2!=0) 
         puts("What a pity!");
        else
       printf("Wonderful!\n");
    }
    return 0;
}

然后根据经过一步操作可到达必败状态的都是必胜状态，下一步操作都是必胜状态，那么这步操作时必败状态的原则一步步的去画表格就可以了。