
方法1: 这题我们可以枚举出所有罗马数字的组合,然后遍历num。时间复杂1,因为最多output长度为15,是一个定值。空间复杂1.
class Solution {
public String intToRoman(int num) {
int[] values = {1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1};
String[] symbols = {"M","CM","D","CD","C","XC","L","XL","X","IX","V","IV","I"};
StringBuilder sb = new StringBuilder();
while(num > 0){
for(int i = 0; i < values.length; ++i){
if(values[i] <= num){
sb.append(symbols[i]);
num -= values[i];
break;
}
}
}
return sb.toString();
}
}
总结:
- 无
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