HJ9 提取不重复的整数

---

题目：HJ9 提取不重复的整数

https://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1

---

思路：通过to_string将int值转成string, 从后往前把不重复元素存到vector中

代码如下

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
using namespace std;

int main() {
    int input = 0;
    cin >> input;
    string str = to_string(input);
    vector<char> chs;
    for (int i = str.size() - 1; i >= 0; i--) {
        vector<char>::iterator it = find(chs.begin(), chs.end(), str[i]);
        if (it == chs.end()) {
            chs.push_back(str[i]);
        }
    }
    for (auto it = chs.begin(); it != chs.end(); it++) {
        cout << *it;
    }
}

to_string

find

谢谢观看，祝顺利！