题目:HJ5 进制转换
https://www.nowcoder.com/practice/8f3df50d2b9043208c5eed283d1d4da6
思路:计算出每一位对应的数并相加
当为’A’时,对应的数为’A’ - ‘A’ + 10 = 10
当为’B’时,对应的数为’B’ - ‘A’ + 10 = 11
当为’C’时,对应的数为’C’ - ‘A’ + 10 = 12
当为’D’时,对应的数为’D’ - ‘A’ + 10 = 13
当为’E’时,对应的数为’E’ - ‘A’ + 10 = 14
当为’F’时,对应的数为’F’ - ‘A’ + 10 = 15
代码如下
#include <iostream>
#include <string>
#include <cmath>
using namespace std;
int main() {
string input;
getline(cin, input);
size_t pos = input.find("x");
if (pos != string::npos) {
input = input.substr(pos + 1);
}
int count = 0;
for (int i = input.size() - 1; i >=0; i--) {
int num = 0;
if (input[i] >= '0' && input[i] <= '9') {
num = input[i] - '0';
} else {
num = input[i] - 'A' + 10;
}
count += num * pow(16, input.size() - i - 1);
}
cout << count;
}
string::substr用法
string::find用法
谢谢观看,祝顺利!