[week 5][Leetcode] Container With Most Water

本文介绍了一种寻找能盛最多水的两个直线的算法。给定一系列非负整数,每个整数代表坐标上的点高度,通过计算找到两直线与x轴构成的容器能盛最多的水。采用双指针策略,从两端向中间移动,比较每一对直线间的面积并更新最大值。

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  • Question:

Given n non-negative integers a1, a2, ...,an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of linei is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container and n is at least 2. 


  • Analysis:
  • Code:
    class Solution {
    public:
        int maxArea(vector<int>& height) {
            int water = 0;
            int lpoint = 0,rpoint = height.size() - 1;
            while (lpoint < rpoint)
            {
                water = max(water,min(height[lpoint],height[rpoint])*(rpoint - lpoint));
                if (height[lpoint] > height[rpoint]) rpoint--;
                else lpoint++;
            }
            return water;
        }
    };

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