Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2, return 1->2.
For example,
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.
正好复习一下链表,感觉要比数组简单一点。
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *deleteDuplicates(ListNode *head) {
ListNode *temp = head;
if(!temp) {
return head;
}
while(temp -> next) {
if(temp -> val == temp -> next -> val) {
temp -> next = temp -> next -> next;
}
else {
temp = temp -> next;
}
}
return head;
}
};