PTA 乙级 1057 数零壹

代码实现：

#include<stdio.h>
#include<string.h>

int main()
{
	char str[100001];
	int sum = 0, cnt_0 = 0, cnt_1 = 0;

	gets(str);
	for (int i = 0; i < strlen(str); i++)
		if (str[i] >= 'a'&&str[i] <= 'z')sum += str[i] - 'a' + 1;
		else if (str[i] >= 'A'&&str[i] <= 'Z')sum += str[i] - 'A' + 1;
	do
	{
		if (sum % 2 == 0 && sum != 0)cnt_0++;
		else if (sum % 2 == 1)cnt_1++;
		sum /= 2;
	} while (sum!= 0);
	printf("%d %d", cnt_0, cnt_1);

	return 0;
}