《ACM程序设计》书中题目 L-12 字符串倒置

本文介绍了如何解决ACM程序设计题目L-12,该题要求输入字符串并将其倒置。样例输入和输出展示了包含空格的字符串处理。提供的C++代码利用`gets()`吸收空格并使用`reverse()`函数实现字符串反转。

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Description

In most languages, text is written from left to right. However, there are other languages where text is read and written from right to left. As a first step towards a program that automatically translates from a left-to-right language into a right-to-left language and back, you are to write a program that changes the direction of a given text.


Input Specification

The input contains several test cases. The first line contains an integer specifying the number of test cases. Each test case consists of a single line of text which contains at most 70 characters. However, the newline character at the end of each line is not considered to be part of the line.


Output Specification

For each test case, print a line containing the characters of the input line in reverse order.


Sample Input

3
Frankly, I don't think we'll make much
money out of this scheme.
madam I'm adam


Sample Output

hcum ekam ll'ew kniht t'nod I ,ylknarF
.emehcs siht fo tuo yenom
mada m'I madam


  这道题的基本题意为输入n行字符串,将各行字符串倒序输出。

  源代码如下:

#include<bits/stdc++.h>
using namespace std;
int main()
{   char c[100];
  string a;
  int n,i;
  cin>>n;
  cin.get();
  while(n--)
  {
  gets(c);
  a=c;
  reverse(a.begin(),a.end());
  cout<<a<<endl;
    }
}

  这道题输入的字符串中包含空格,所以要用gets输入,但是gets也能输入空行,所以这道题的难点就在于将输入n后的空格吸收掉。

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