#include<stdio.h>
int main()
{
int i,n,m,a,b;
while(scanf("%d",&n)!=EOF)
{
int first=1,x[2001]={0};
for(i=0;i<n;i++)
{
scanf("%d%d",&a,&b);
x[b+1000]=a;
}
scanf("%d",&m);
for(i=0;i<m;i++)
{
scanf("%d%d",&a,&b);
x[b+1000]+=a;
}
for(i=2000;i>=0;i--)
{
if(x[i]==0)
continue;
if(first)
first=0;
else
printf(" ");
printf("%d %d",x[i],i-1000);
}
printf("\n");
}
return 0;
}
/**************************************************************
Problem: 1472
User: cust123
Language: C++
Result: Accepted
Time:10 ms
Memory:1020 kb
****************************************************************/
题目1472:求两个多项式的和
最新推荐文章于 2024-03-19 22:45:48 发布