A-1001 A+B Format (20 分)
Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −10
6
≤a,b≤10
6
. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
#include <string>
#include <iostream>
using namespace std;
int main(){
int a,b,sum,i,j;
int str[15]={};
cin >> a >> b;
sum=a+b;
if(sum==0)cout << sum;
if(sum<0){
cout<<"-";
sum=-sum;
}
for(i=1;sum>0;i++){//将每一位数字存入数组中
str[i]=sum%10;
sum/=10;
}
for(j=i-1;j>=1;j--){
cout << str[j];
if(j%3==1&&j>1)cout << ",";
}
return 0;
}
本文介绍了一个简单的C++程序,该程序接收两个整数输入,并以标准格式输出这两个整数的和,即每三位数字用逗号分隔。

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