Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [-2,1,-3,4,-1,2,1,-5,4]
,
the contiguous subarray [4,-1,2,1]
has the largest sum = 6
.
计算子数列的最大和,设定一个x,x目前为止的最大值,y为部分数的和,y从第一位开始,逐次求其与后一位的和,一旦y<0,则y归零,每一次取得的y值与x进行比较,如果y>x,则x=y,否则继续。当所有的数都进行运算之后,x的值即为所求。
#include<vector>
#include<iostream>
using namespace std;
int maxSubArray(vector<int>& nums) {
int a = nums[0];
int x,y,sum = 0;
int num = nums.size();
for(int b = 0; b < num; b++){
sum += nums[b];
a = max(sum, a);
sum = max(sum, 0);
}
return a;
}
int main()
{
vector<int> nums;
int c, n;
cin >> n;
for(int a = 0; a < n; a++){
cin >> c;
nums.push_back(c) ;
}
int b = maxSubArray(nums);
cout << b ;
return 0;
}