K - s-palindrome（水坑）

 

坑点：p和q，b和d成镜像，小写m和i不和自身成镜像

#include<iostream>
#include<cstring>

using namespace std;
//按ascill码表的顺序对应各自的镜像字母，不成镜像用*表示
char st[100] = "A******HI***M*O****TUVWXY********d*b**********oqp****vwx****";
char s[2005];
char s2[2005];
char zhuan(char c){
	return st[c -'A'];
}

int main(){
	cin >> s;
	int len = strlen(s);
	int flag = 1;
	for( int i = 0 ; i < len ; ++i ){
		s2[i] = s[len-i-1];
	}
	for( int i = 0 ; i < len ; ++i ){
		if(s[i] != zhuan(s2[i])){
			flag = 0;
			break;
		}
	}
		if(flag){
			cout << "TAK" << endl;
		}
		else{
			cout << "NIE" << endl;
		}
	return 0;
}