1. Two Sum
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
class Solution {
public:
vector<int> twoSum(vector<int>& nums, int target) {
vector<int> result;
for (int i = 0; i < nums.size(); i++)
{
for (int j = i+1; j < nums.size(); j++)
{
if (nums[j] == target-nums[i])
{
result.push_back(i);
result.push_back(j);
break;
}
}
}
return result;
}
};

本文介绍了一个经典的编程面试题——TwoSum问题。给定一个整数数组及目标值,找到两个数的索引使得它们相加等于目标值。文章提供了一个C++实现的解决方案,并详细解释了如何遍历数组寻找符合条件的元素。
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