LeetCode:Find Minimum in Rotated Sorted Array
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7
might become 4 5 6 7 0 1 2
).
Find the minimum element.
You may assume no duplicate exists in the array.
解法一:遍历。。。时间复杂度O(n)<span style="white-space:pre"> </span>int res = num[0];
for(int i=1; i<num.size(); i++)
{
if(num[i]<res)
return num[i];
}
return res;
解法二:二分法查找
<span style="white-space:pre"> </span>int begin = 0;
int end = num.size()-1;
int mid=begin;
while(num[begin] > num[end])
{
if(end - begin == 1)
{
mid = end;
break;
}
mid = (begin+end)/2;
if(num[mid]>num[begin])
{
begin = mid;
}
else if(num[mid]<num[end])
{
end = mid;
}
}
return num[mid];