题意:给定两个字符串s1和s2,如果能通过s1循环移位,使s2包含在s1中,那么我们就说s2 是s1的亲和串。
题解:把第一个字符串扩展为2倍,然后kmp
#include <cstdio>
#include <iostream>
#include <cstring>
#include <string>
#include <cmath>
#include <set>
using namespace std;
const int maxn = 100005;
char s[2*maxn],s1[maxn],s2[maxn];
int len,len1,Next[maxn];
void Get_next()
{
int i = 0,j = -1;
Next[0] = -1;
while(i < len1)
{
if(j == -1 || s[i] == s1[j])
{
i++;
j++;
Next[i] = j;
}
else
j = Next[j];
}
}
int kmp()
{
int i = 0,j = 0,flag = 0;
while(i < len)
{
if(s[i] == s1[j] || j == -1)
{
i++;
j++;
//printf("%d %d\n",i,j);
}
else
{
// printf("%d\n",j);
j = Next[j];
}
if(j == len1)
{
flag = 1;
break;
}
//printf("%d %d\n",i,j);
}
return flag;
}
int main()
{
int t,c = 1;
while(scanf("%s%s",s,s1) == 2)
{
len = strlen(s);
len1 = strlen(s1);
if(len < len1)
{
printf("no\n");
continue;
}
for(int i = len; i < len * 2; i++)
s[i] = s[i-len];
len *= 2;
Get_next();
printf("%s\n",kmp() == 1? "yes" : "no");
}
return 0;
}