方法一:
通过数学的方法,取余和相除求出其个十百千位,根据题意构建if判断语句
处理好判断部分的%和/
n = 5
m = []
for i in range(5):
m = m + input().split()
l = list(map(int,m))
s = 0
for i in range(5):
if int(l[i]/1000) == int((l[i]%100)/10) and (l[i]%10)-1 == int((l[i]%1000)/100):
s = s+1
print(s)
方法二:
更简洁的方法,只需要判断位置
n = 5
l = []
for i in range(5):
l = l + input().split()
s = 0
for i in range(5):
m = []
m = list(map(str,l[i]))# 将每一个年份字符串都拆分为一个字符列表,只需要在位置上进行判断
if m[0] == m[2] and int(m[3]) == int(m[1]) + 1:
s = s+1
print(s)