反思:题目本身很简单,不过一定要注意输出,这个题目的输出是Yes和No,不是YES和NO,不要WA在这个地方
#include <iostream>
#include <queue>
#include <cstdio>
#include <map>
#include <cstring>
#include <stack>
#include <string>
#include <vector>
#include <cmath>
using namespace std;
const int INF = 1 << 30;
const int maxn = 40;
struct Node
{
int v;
double w;
Node(){}
Node(int vv, double ww) : v(vv), w(ww) {}
};
int n, m;
vector<vector<Node> > G;
map<string, int> ind;
double dis[maxn];
int update[maxn];
void Init()
{
memset(update, 0, sizeof(update));
for (int i = 1; i <= n; i++) {
dis[i] = 0;
}
G.resize(n + 1);
for (int i = 1; i <= n; i++) {
G[i].clear();
}
}
int SPFA(int v)
{
queue<int> q;
q.push(v);
dis[v] = 1;
while (!q.empty()) {
int t = q.front();
q.pop();
for (int i = 0, j = G[t].size(); i < j; i++) {
Node tmp = G[t][i];
//cout << tmp.v << endl;
double md = tmp.w * dis[t];
if (md > dis[tmp.v]) {
dis[tmp.v] = md;
update[tmp.v]++;
if (update[tmp.v] >= n) {
return 1;
}
q.push(tmp.v);
}
}
}
return 0;
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("in.txt", "r", stdin);
//freopen("out.txt", "w", stdout);
#endif // ONLINE_JUDGE
int kase = 1;
while (cin >> n) {
if (n == 0) break;
Init();
string s;
for (int i = 1; i <= n; i++) {
cin >> s;
ind[s] = i;
}
cin >> m;
string s1, s2;
double r;
for (int i = 0; i < m; i++) {
cin >> s1 >> r >> s2;
int a1 = ind[s1];
int a2 = ind[s2];
G[a1].push_back(Node(a2, r));
}
int flag = SPFA(1);
cout << "Case " << kase++ << ": ";
if (flag) {
cout << "Yes" << endl;
} else {
cout << "No" << endl;
}
}
return 0;
}