题目:
You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
代码:
int climbStairs(int n)
{
if (n == 1)
return 1;
if (n == 2)
return 2;
int res = 0;
int f_1 = 1;
int f_2 = 2;
for (int i = 3; i <= n; ++i)
{
res = f_1 + f_2;
f_1 = f_2;
f_2 = res;
}
return res;
}
本文探讨了一个经典的算法问题——爬楼梯。通过递推的方法,实现了高效求解不同台阶数时的组合方式数量。该算法利用了动态规划的思想,避免了重复计算,是一种简洁高效的解决方案。
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