HDU 1047

杭电oj 1047习题 立即下载
#include<stdio.h>
#include<string.h>
int main()
{
    int t,i,j,len,a[11000],b[11000],min,c,temp,sum;
    char s[10000];
    scanf("%d",&t);
    while(t--)
    {
        memset(a,0,sizeof(a));
        while(scanf("%s",s)&&!(strlen(s)==1&&s[0]=='0'))
        {
            memset(b,0,sizeof(b));
            len=strlen(s);
            for(i=len-1;i>=0;i--)
                b[len-i-1]=s[i]-'0';
            for(i=0,c=0;i<10000;i++)
            {
                sum=a[i]+b[i]+c;
                a[i]=sum%10;
                c=sum/10;
            }
        }
        i=10999;
        while(!a[i--])
            if(i<0)
                break;
        for(i++;i>=0;i--)
            printf("%d",a[i]);
        printf("\n");
        if(t!=0)
            printf("\n");
    }
}

音视频从入门到精通——指数哥伦布码原理 在计算机中,一般数字的编码都为二进制,但是由于以相等长度来记录不同数字,因此会出现很多的。 阅读详情

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