CodeForces - 4A Watermelon

Watermelon

One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed w kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.

Pete and Billy are great fans of even numbers, that’s why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that’s why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.

Input
The first (and the only) input line contains integer number w (1 ≤ w ≤ 100) — the weight of the watermelon bought by the boys.

Output
Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.

Examples
Input
8
Output
YES

Note
For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).
问题连接

问题描述

天热了,有两个人想要吃西瓜，然后他们就买了个西瓜，但是他们同时还是偶数爱好者，痴迷到想把西瓜分成两部分，这两部分都要是偶数，甚至不均分也没关系。我们的任务就是判断这个西瓜有没有可能符合他们的要求

问题分析

只需要判断西瓜的质量是否大于2且是偶数，因为2只能分成1和1，奇数只能分成奇数+奇数。

c++程序如下

#include<iostream>
using namespace std;
int main()
{
	int w;
	cin>>w;
	if(w>2&&w%2==0)cout<<"YES\n";
	else cout<<"NO\n";
	return 0;
}