PAT乙级1036

题目链接

实现

#include <iostream>
#include <cmath>
using namespace std;

int main()
{
	int lie;
	int hang;
	char character;
	cin >> lie >> character;
	hang = round(lie*1.0 / 2);

	for (int i = 0; i < hang; i++)
	{
		if (i == 0 || i == hang - 1)
		{
			for (int j = 0; j < lie; j++)
				cout << character;
		}
		else
		{
			
			for (int m = 0; m < lie; m++)
			{
				if (m == 0 || m == lie - 1)
					cout << character;
				else
					cout << " ";
			}

		}
		cout << endl;
	}
    return 0;
}