1. poj 1088
#include<cstdio>
#include<cmath>
#include<stdlib.h>
#include<map>
#include<set>
#include<time.h>
#include<vector>
#include<queue>
#include<string>
#include<string.h>
#include<iostream>
#include<algorithm>
using namespace std;
#define eps 1e-8
#define PI acos(-1.0)
#define INF 0x3f3f3f3f
#define LL long long
#define max(a,b) ((a)>(b)?(a):(b))
#define min(a,b) ((a)<(b)?(a):(b))
typedef pair<int , int> pii;
#define maxn 100 + 10
int d[maxn][maxn];
int a[maxn][maxn];
int go[4][2] = {{1, 0}, {-1, 0}, {0, 1}, {0, -1}};
int R, C;
int ans;
int dfs(int x, int y)
{
if(d[x][y] > 0) return d[x][y];
int res = 0;
for(int i = 0; i < 4; i++)
{
int dx = x + go[i][0];
int dy = y + go[i][1];
if(dx < 1 || dy < 1 || dx > R || dy > C || a[dx][dy] >= a[x][y]) continue;
int t = dfs(dx, dy);
res = max(res, t);
}
res++;
ans = max(ans, res);
return d[x][y] = res;
}
int main()
{
while(~scanf("%d%d", &R, &C))
{
ans = -INF;
for(int i = 1; i <= R; i++)
for(int j = 1; j <= C; j++)
scanf("%d", &a[i][j]);
memset(d, -1, sizeof d);
for(int i = 1; i <= R; i++)
for(int j = 1; j <= C; j++)
if(d[i][j] < 0)
dfs(i, j);
printf("%d\n", ans);
}
return 0;
}
2.poj2299
#include<cstdio>
#include<cmath>
#include<stdlib.h>
#include<map>
#include<set>
#include<time.h>
#include<vector>
#include<queue>
#include<string>
#include<string.h>
#include<iostream>
#include<algorithm>
using namespace std;
#define eps 1e-8
#define PI acos(-1.0)
#define INF 0x3f3f3f3f
#define LL long long
#define max(a,b) ((a)>(b)?(a):(b))
#define min(a,b) ((a)<(b)?(a):(b))
typedef pair<int , int> pii;
#define maxn 500000 + 10
int a[maxn];
int n;
int lowbit(int x)
{
return x & (-x);
}
void modify(int x,int add)//一维
{
while(x<=n)
{
a[x]+=add;
x+=lowbit(x);
}
}
int get_sum(int x)
{
int ret=0;
while(x > 0)
{
ret+=a[x];
x-=lowbit(x);
}
return ret;
}
map<int, int> M;
set<int> S;
struct B
{
int x, pos;
}b[maxn];
int cmp(B t1, B t2)
{
return t1.x < t2.x ;
}
int bb[maxn];
int main()
{
while(~scanf("%d", &n) && n)
{
for(int i = 1; i <= n; i++)
{
scanf("%d", &b[i].x);
b[i].pos = i;
}
sort(b + 1, b + 1 + n, cmp);
for(int i = 1; i <= n; i++)
bb[b[i].pos] = i;
memset(a, 0, sizeof a);
LL ans = 0;
for(int i = 1 ; i <= n; i++)
{
modify(bb[i], 1);
ans += i - get_sum(bb[i]);
}
printf("%I64d\n", ans);
}
return 0;
}
/*
5
9
1
0
5
4
3
1
2
3
0
*/
3. hdu
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>
using namespace std;
#define maxn 400000 + 10
int L[maxn], R[maxn];
int pos[maxn];
int a[maxn];
int n;
void get_left()
{
int head = 1, tail = 0;
for(int i = 1; i <= n; i++)
{
while(head <= tail && a[pos[tail]] >= a[i])
tail--;
L[i] = i - pos[tail] - 1;
pos[++tail] = i;
}
}
void get_right()
{
int head = 1, tail = 0;
pos[tail] = n + 1;
for(int i = n; i >= 1; i--)
{
while(head <= tail && a[pos[tail]] >= a[i])
tail--;
R[i] = pos[tail] - i - 1;
pos[++tail] = i;
}
}
int main()
{
while(~scanf("%d", &n))
{
memset(L, 0, sizeof L);
memset(R, 0, sizeof R);
for(int i = 1; i <= n; i++)
scanf("%d", a + i);
get_left();
get_right();
for(int i = 1; i <= n; i++)
{
printf("%d * %d\n", L[i], R[i]);
}
long long ans = -1;
for(int i = 1; i <= n; i++)
ans = max(ans, ((long long)L[i] + R[i] + 1) * a[i]);
printf("%I64d\n", ans);
}
return 0;
}
/*
6
5 8 4 4 8 4
*/
4.hdu 1541
#include<cstdio>
#include<cmath>
#include<stdlib.h>
#include<map>
#include<set>
#include<time.h>
#include<vector>
#include<queue>
#include<string>
#include<string.h>
#include<iostream>
#include<algorithm>
using namespace std;
#define eps 1e-8
#define PI acos(-1.0)
#define INF 0x3f3f3f3f
#define LL long long
#define max(a,b) ((a)>(b)?(a):(b))
#define min(a,b) ((a)<(b)?(a):(b))
typedef pair<int , int> pii;
#define N 32010
#define maxn 15010
int n;
int a[N];
int ans[maxn];
int lowbit(int x)
{
return x & (-x);
}
void modify(int x, int add)
{
while(x <= N)
{
a[x] += add;
x += lowbit(x);
}
}
int get_sum(int x)
{
int ret = 0;
while(x > 0)
{
ret += a[x];
x -= lowbit(x);
}
return ret;
}
int main()
{
while(~scanf("%d", &n))
{
int x, y;
memset(ans, 0, sizeof ans);
memset(a, 0, sizeof a);
for(int i = 0; i < n; i++)
{
scanf("%d%d", &x, &y);
x++;
ans[get_sum(x)]++;
modify(x, 1);
}
for(int i = 0; i < n; i++)
printf("%d\n", ans[i]);
}
return 0;
}