Problem - 1010 Kolakoskit(杭电多校签到题)

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本文介绍了一种特殊的数列——Kolakoski序列，并通过编程方式生成该序列的前10^7项。文章详细展示了如何利用C++语言实现这一数列的生成过程，进而快速获取任意指定位置上的数列元素。

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Problem Description

This is Kolakosiki sequence:

1,2,2,1,1,2,1,2,2,1,2,2,1,1,2,1,1,2,2,1……. This sequence consists of

1 and

2, and its first term equals

1. Besides, if you see adjacent and equal terms as one group, you will get

1,22,11,2,1,22,1,22,11,2,11,22,1……. Count number of terms in every group, you will get the sequence itself. Now, the sequence can be uniquely determined. Please tell HazelFan its

nth element.

Input

The first line contains a positive integer

T(1≤T≤5), denoting the number of test cases.
For each test case:
A single line contains a positive integer

n(1≤n≤107).

Output

For each test case:
A single line contains a nonnegative integer, denoting the answer.

Sample Input

2
1
2

Sample Output

1
2



分析：
按照规律打表，直接输出即可。

#include<bits/stdc++.h>
using namespace std;
int a[10000005];
int f[5];
int main()
{
    int t,sum=1,k=2,z=2,n;
    cin>>t;
    a[1]=1;a[2]=2;
    for(long long i=3;i<=10000005;i++)
    {
        sum++;
        a[i]=z;
        if(sum==a[k])
        {
            sum=0;k++;
            if(z==2) z=1;
            else z=2;
        }
    }
    while(t--)
    {
        cin>>n;
        cout<<a[n]<<endl;
    }
}