LeetCode Same Tree

最新推荐文章于 2020-07-27 10:14:22 发布

原创最新推荐文章于 2020-07-27 10:14:22 发布 · 605 阅读

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本文将详细阐述如何通过广度优先搜索算法判断两个二叉树是否等价，深入探讨二叉树结构的比较方法及实现细节。

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Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

判断两个二叉树是否相同，广搜！

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
#include <queue>
using namespace std;
class Solution {
public:
    bool isSameTree(TreeNode *p, TreeNode *q) {
        if (p == NULL && q == NULL)
            return true;
        if (p == NULL)
            return false;
        if (q == NULL)
            return false;
        queue<TreeNode *> l1, l2;
        l1.push(p);
        l2.push(q);
        TreeNode *tmp1;
        TreeNode *tmp2;
        while (!l1.empty() && !l2.empty()) {
            tmp1 = l1.front();
            l1.pop();
            tmp2 = l2.front();
            l2.pop();
            if (tmp1->val != tmp2->val)
                return false;
            if (tmp1->left!=NULL && tmp2->left!=NULL) {
                l1.push(tmp1->left);
                l2.push(tmp2->left);
            }
            else if (!(tmp1->left==NULL&&tmp2->left==NULL))
                return false;
            if (tmp1->right!=NULL && tmp2->right!=NULL) {
                l1.push(tmp1->right);
                l2.push(tmp2->right);
            }
            else if (!(tmp1->right==NULL&&tmp2->right==NULL))
                return false;
        }
        if (l1.empty() && l2.empty())
            return true;
        else
            return false;
    }
};