Codeforces Round 307 Div 2

本文深入探讨了人工智能和大数据领域的最新趋势和技术应用,包括机器学习、深度学习、数据挖掘、自然语言处理等前沿话题,揭示了这些技术如何推动社会进步与产业发展。
A. GukiZ and Contest
time limit per test
 2 seconds
memory limit per test
 256 megabytes
input
 standard input
output
 standard output

Professor GukiZ likes programming contests. He especially likes to rate his students on the contests he prepares. Now, he has decided to prepare a new contest.

In total, n students will attend, and before the start, every one of them has some positive integer rating. Students are indexed from 1 to n. Let's denote the rating of i-th student as ai. After the contest ends, every student will end up with some positive integer position. GukiZ expects that his students will take places according to their ratings.

He thinks that each student will take place equal to . In particular, if student A has rating strictly lower then student BA will get the strictly better position than B, and if two students have equal ratings, they will share the same position.

GukiZ would like you to reconstruct the results by following his expectations. Help him and determine the position after the end of the contest for each of his students if everything goes as expected.

Input

The first line contains integer n (1 ≤ n ≤ 2000), number of GukiZ's students.

The second line contains n numbers a1, a2, ... an (1 ≤ ai ≤ 2000) where ai is the rating of i-th student (1 ≤ i ≤ n).

Output

In a single line, print the position after the end of the contest for each of n students in the same order as they appear in the input.

Sample test(s)
input
3
1 3 3
output
3 1 1
input
1
1
output
1
input
5
3 5 3 4 5
output
4 1 4 3 1
Note

In the first sample, students 2 and 3 are positioned first (there is no other student with higher rating), and student 1 is positioned third since there are two students with higher rating.

In the second sample, first student is the only one on the contest.

In the third sample, students 2 and 5 share the first position with highest rating, student 4 is next with third position, and students 1 and 3are the last sharing fourth position.

求每个数在排好序中的位置,暴力。。(一开始准备线段树,看了数据范围果断暴力




B. ZgukistringZ
time limit per test
 2 seconds
memory limit per test
 256 megabytes
input
 standard input
output
 standard output

Professor GukiZ doesn't accept string as they are. He likes to swap some letters in string to obtain a new one.

GukiZ has strings ab, and c. He wants to obtain string k by swapping some letters in a, so that k should contain as many non-overlapping substrings equal either to b or c as possible. Substring of string x is a string formed by consecutive segment of characters from x. Two substrings of string x overlap if there is position i in string x occupied by both of them.

GukiZ was disappointed because none of his students managed to solve the problem. Can you help them and find one of possible stringsk?

Input

The first line contains string a, the second line contains string b, and the third line contains string c (1 ≤ |a|, |b|, |c| ≤ 105, where |s|denotes the length of string s).

All three strings consist only of lowercase English letters.

It is possible that b and c coincide.

Output

Find one of possible strings k, as described in the problem statement. If there are multiple possible answers, print any of them.

Sample test(s)
input
aaa
a
b
output
aaa
input
pozdravstaklenidodiri
niste
dobri
output
nisteaadddiiklooprrvz
input
abbbaaccca
ab
aca
output
ababacabcc
Note

In the third sample, this optimal solutions has three non-overlaping substrings equal to either b or c on positions 1 – 2 (ab), 3 – 4 (ab),5 – 7 (aca). In this sample, there exist many other optimal solutions, one of them would be acaababbcc.



给3个字符串a,b,c求c经过重排,最多可构成不重复b,c多少个

比赛时想过先对b求,再求a,但没证出这是对的。。。。

好吧,正解就是先对b求c的前部分,再对a求。。。


C. GukiZ hates Boxes
time limit per test
 2 seconds
memory limit per test
 256 megabytes
input
 standard input
output
 standard output

Professor GukiZ is concerned about making his way to school, because massive piles of boxes are blocking his way.

In total there are n piles of boxes, arranged in a line, from left to right, i-th pile (1 ≤ i ≤ n) containing ai boxes. Luckily, m students are willing to help GukiZ by removing all the boxes from his way. Students are working simultaneously. At time 0, all students are located left of the first pile. It takes one second for every student to move from this position to the first pile, and after that, every student must start performing sequence of two possible operations, each taking one second to complete. Possible operations are:

  1. If i ≠ n, move from pile i to pile i + 1;
  2. If pile located at the position of student is not empty, remove one box from it.

GukiZ's students aren't smart at all, so they need you to tell them how to remove boxes before professor comes (he is very impatient man, and doesn't want to wait). They ask you to calculate minumum time t in seconds for which they can remove all the boxes from GukiZ's way. Note that students can be positioned in any manner after t seconds, but all the boxes must be removed.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 105), the number of piles of boxes and the number of GukiZ's students.

The second line contains n integers a1, a2, ... an (0 ≤ ai ≤ 109) where ai represents the number of boxes on i-th pile. It's guaranteed that at least one pile of is non-empty.

Output

In a single line, print one number, minimum time needed to remove all the boxes in seconds.

Sample test(s)
input
2 1
1 1
output
4
input
3 2
1 0 2
output
5
input
4 100
3 4 5 4
output
5
Note

First sample: Student will first move to the first pile (1 second), then remove box from first pile (1 second), then move to the second pile (1 second) and finally remove the box from second pile (1 second).

Second sample: One of optimal solutions is to send one student to remove a box from the first pile and a box from the third pile, and send another student to remove a box from the third pile. Overall, 5 seconds.

Third sample: With a lot of available students, send three of them to remove boxes from the first pile, four of them to remove boxes from the second pile, five of them to remove boxes from the third pile, and four of them to remove boxes from the fourth pile. Process will be over in 5 seconds, when removing the boxes from the last pile is finished.


小孩搬石头,移动和搬都是花费时间1,求最小的时间花费



贪心+二分

太弱了以为是dp想了半天弃疗了

反过来判断即可,(反过来直接加,正的不好判断


#include<cstdio>
#include<cstring>
#include<iostream>
#include<queue>
#define M 100010


using namespace std;


typedef long long ll;
int b[M],a[M],cnt,n,m;
ll sum;
bool check(ll x)
{
    for(int i=1;i<=n;i++)
    b[i]=a[i];
    cnt=n;
    ll tmp=0;
    for(int i=1;i<=m;i++)
    {
        while(cnt>0&&b[cnt]==0)
        cnt--;
        if(cnt==0)return true;
        tmp=cnt;
        while(cnt>0&&b[cnt]+tmp<=x)
        {
            tmp+=b[cnt];
            b[cnt]=0;
            cnt--;
        }
        if(cnt==0)
        return true;
        b[cnt]-=(x-tmp);
    }
    return false;
}



int main()
{
    scanf("%d%d",&n,&m);
    sum=n;
    for(int i=1;i<=n;i++)
    {
        scanf("%d",&a[i]);
        sum+=a[i];
    }
    ll l=0,r=sum,mid;
    while(l<r)
    {
        mid=l + r >>1;
        if(check(mid))
        r=mid;
        else
        l=mid+1;
    }
    printf("%I64d\n",l);
    return 0;
}






### Codeforces Round 1028 (Div. 2) 题目概述 Codeforces Round 1028 (Div. 2) 是一场包含多个算法问题的比赛,涵盖了从简单到复杂的不同难度级别。以下是该比赛的部分题目内容及简要说明: #### A. Gellyfish and Flower 在本题中,有两个角色:Gellyfish 和 Flower。每个角色有两滴血量,分别用 \(a\) 和 \(c\) 表示 Gellyfish 的血量,用 \(b\) 和 \(d\) 表示 Flower 的血量[^3]。 获胜条件是攻击对方的最低血量,并比较双方的最低血量值。如果 Gellyfish 的最低血量小于 Flower 的最低血量,则 Gellyfish 获胜;否则,Flower 获胜。 #### B. Problem - B - Codeforces B 题的具体内容未完全提供,但通常涉及数组、字符串或其他数据结构的操作。可以参考比赛页面获取完整描述。 #### C. Rectangles C 题要求处理矩形的相关问题。具体来说,给定一些矩形的边长信息,需要判断某些条件是否满足。时间限制为每组测试用例 2 秒,内存限制为 256 MB[^2]。输入和输出均为标准格式,详细规则可参考比赛页面。 ### 示例代码(A 题) 以下是一个实现 A 题逻辑的 C++ 程序: ```cpp #include <iostream> #include <algorithm> using namespace std; int main() { int t; cin >> t; while (t--) { int a, b, c, d; cin >> a >> b >> c >> d; int mina = min(a, c); int minb = min(b, d); if (mina < minb) cout << "Flower" << endl; else cout << "Gellyfish" << endl; } } ``` 此代码通过多次循环读取输入并计算两个角色的最低血量,最终输出获胜者名称。 ### 注意事项 - 比赛中的所有题目均可以通过官方链接访问,例如 [Codeforces Round 1028 (Div. 2)](http://codeforces.com/contest/1028)[^2]。 - 每道题目的详细规则和样例输入输出可在对应页面找到。
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