hdu Problem-5703

本文探讨了在沙漠中一名游客如何用有限的水量求生的问题。通过编程计算不同天数下消耗特定升数水的所有可能方式,并以二进制形式展示结果。

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Desert

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)
Total Submission(s): 1126    Accepted Submission(s): 803


Problem Description
A tourist gets lost in the desert with n liters of water. He drinks positive integer units of water each day.

Write a program to calculate how many different ways the tourist can drink up the water.
 

Input
The first line contains the number of test cases T(T10).
Next T lines contain the number n(1n1000000) for each test case.
 

Output
Output consists of T lines.
Each line contains the binary number which represents number of different ways to finish up the water specified in the test case.
 

Sample Input
1 3
 

Sample Output
100
Hint
3 liters of water can be comsumed in four different ways show in the following. 1. 1 1 1 2. 1 2 3. 2 1 4. 3 If we write 4 in binary, it's 100.


//思路:找规律

AC源码:

#include <iostream>
using namespace std;

int main()
{
	int T,n;
	cin>>T;
	while(T--)
	{
		cin>>n;
		cout<<"1";
		while(--n)
			cout<<"0";
		cout<<endl;
	}
	return 0;
}




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