一、问题
1
2 3
4 5 6
7
输出该树中序遍历的结果
二、代码
Java
@Data
public class Node {
private Integer id;
private Node left;
private Node right;
public Node(Integer id) {
this.id = id;
}
public Node(Integer id, Node left, Node right) {
this.id = id;
this.left = left;
this.right = right;
}
}
@Data
public class Tree {
private Node root;
/**
* 建树 【V80】
*
* 1
* 2 3
* 4 5 6
* 7
*/
public void build() {
Node node7 = new Node(7);
Node node6 = new Node(6);
Node node5 = new Node(5, node7, null);
Node node4 = new Node(4);
Node node3 = new Node(3, node5, node6);
Node node2 = new Node(2, null, node4);
root = new Node(1, node2, node3);
}
/**
* 中序遍历(非递归)
*/
public void middleOrder(Node root) {
if (root == null) {
return;
}
if (root == null) {
return;
}
//栈里所有的节点中:如果有左右孩子,其左右孩子已经入栈的节点
Map<Integer, Boolean> childHasEnHeapMap = new HashMap<>();
Deque<Node> heap = new LinkedList<>();
heap.offerLast(root);
while (!heap.isEmpty()) {
Node top = heap.pollLast();
Boolean childHasEnHeap = childHasEnHeapMap.get(top.getId());
if (childHasEnHeap == null) {
if (top.getRight() != null) {
heap.offerLast(top.getRight());
}
heap.offerLast(top);
if (top.getLeft() != null) {
heap.offerLast(top.getLeft());
}
//左右孩子已入栈
childHasEnHeapMap.put(top.getId(), Boolean.TRUE);
} else {
childHasEnHeapMap.remove(top.getId());
System.out.print(top.getId() + " ");
}
}
}
public static void main(String[] args) {
Tree tree = new Tree();
tree.build();
tree.middleOrder(tree.getRoot());
}
}
运行结果
2 4 1 7 5 3 6
三、扩展
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