线段树应用1

Problem - D - Codeforces

#include <bits/stdc++.h>

using i64 = long long;
template<class Info>
struct SegmentTree {
    int n;
    std::vector<Info> info;
    SegmentTree() : n(0) {}
    SegmentTree(int n_, Info v_ = Info()) {
        init(n_, v_);
    }
    template<class T>
    SegmentTree(std::vector<T> init_) {
        init(init_);
    }
    void init(int n_, Info v_ = Info()) {
        init(std::vector(n_, v_));
    }
    template<class T>
    void init(std::vector<T> init_) {
        n = init_.size();
        info.assign(4 << std::__lg(n), Info());
        std::function<void(int, int, int)> build = [&](int p, int l, int r) {
            if (r - l == 1) {
                info[p] = init_[l];
                return;
            }
            int m = (l + r) / 2;
            build(2 * p, l, m);
            build(2 * p + 1, m, r);
            pull(p);
        };
        build(1, 0, n);
    }
    void pull(int p) {
        info[p] = info[2 * p] + info[2 * p + 1];
    }
    void modify(int p, int l, int r, int x, const Info &v) {
        if (r - l == 1) {
            info[p] = v;
            return;
        }
        int m = (l + r) / 2;
        if (x < m) {
            modify(2 * p, l, m, x, v);
        } else {
            modify(2 * p + 1, m, r, x, v);
        }
        pull(p);
    }
    void modify(int p, const Info &v) {
        modify(1, 0, n, p, v);
    }
    Info rangeQuery(int p, int l, int r, int x, int y) {
        if (l >= y || r <= x) {
            return Info();
        }
        if (l >= x && r <= y) {
            return info[p];
        }
        int m = (l + r) / 2;
        return rangeQuery(2 * p, l, m, x, y) + rangeQuery(2 * p + 1, m, r, x, y);
    }
    Info rangeQuery(int l, int r) {
        return rangeQuery(1, 0, n, l, r);
    }
    template<class F>
    int findFirst(int p, int l, int r, int x, int y, F pred) {
        if (l >= y || r <= x || !pred(info[p])) {
            return -1;
        }
        if (r - l == 1) {
            return l;
        }
        int m = (l + r) / 2;
        int res = findFirst(2 * p, l, m, x, y, pred);
        if (res == -1) {
            res = findFirst(2 * p + 1, m, r, x, y, pred);
        }
        return res;
    }
    template<class F>
    int findFirst(int l, int r, F pred) {
        return findFirst(1, 0, n, l, r, pred);
    }
    template<class F>
    int findLast(int p, int l, int r, int x, int y, F pred) {
        if (l >= y || r <= x || !pred(info[p])) {
            return -1;
        }
        if (r - l == 1) {
            return l;
        }
        int m = (l + r) / 2;
        int res = findLast(2 * p + 1, m, r, x, y, pred);
        if (res == -1) {
            res = findLast(2 * p, l, m, x, y, pred);
        }
        return res;
    }
    template<class F>
    int findLast(int l, int r, F pred) {
        return findLast(1, 0, n, l, r, pred);
    }
};

int n, v;

constexpr int inf = 1 << 30;
struct Info {
    std::pair<int, int> l[30];
    std::pair<int, int> r[30];
    int ans;
    int max;
    
    Info(int b = 0, int a = 0) {
        int p = 0, q = 0;
        for (int i = 0; i < 30; i++) {
            if (b >> i & 1) {
                l[p++] = {a, i};
                r[q++] = {a, i};
            }
        }
        for (int i = 0; i < 30; i++) {
            if (~b >> i & 1) {
                l[p++] = {inf, i};
                r[q++] = {inf, i};
            }
        }
        ans = b >= v ? a : inf;
        max = a;
    }
};

Info operator+(const Info &a, const Info &b) {
    Info c;
    c.ans = std::min(a.ans, b.ans);
    c.max = std::max(a.max, b.max);
    int xa = (1 << 30) - 1;
    int xb = 0;
    for (int i = 29, j = 0; i >= 0; i--) {
        while ((xa | xb) < v) {
            assert(j < 30);
            xb ^= 1 << b.l[j].second;
            j++;
        }
        if (j > 0) {
            int l = a.r[i].first;
            int r = b.l[j - 1].first;
            c.ans = std::min(c.ans, std::max(l, r));
        }
        xa ^= 1 << a.r[i].second;
    }
    int p = 0, q = 0;
    int ma = 0, mb = 0;
    for (int i = 0; i < 30; i++) {
        if (a.l[i].first != inf) {
            c.l[p++] = a.l[i];
            ma |= 1 << a.l[i].second;
        }
        if (b.r[i].first != inf) {
            c.r[q++] = b.r[i];
            mb |= 1 << b.r[i].second;
        }
    }
    for (int i = 0; i < 30; i++) {
        if (~ma >> b.l[i].second & 1) {
            c.l[p++] = {std::max(a.max, b.l[i].first), b.l[i].second};
        }
        if (~mb >> a.r[i].second & 1) {
            c.r[q++] = {std::max(b.max, a.r[i].first), a.r[i].second};
        }
    }
    return c;
}

void solve() {
    std::cin >> n >> v;
    
    std::vector<int> a(n), b(n);
    for (int i = 0; i < n; i++) {
        std::cin >> a[i];
    }
    for (int i = 0; i < n; i++) {
        std::cin >> b[i];
    }
    
    std::vector<Info> init(n);
    for (int i = 0; i < n; i++) {
        init[i] = Info(b[i], a[i]);
    }
    SegmentTree<Info> seg(init);
    
    int q;
    std::cin >> q;
    
    while (q--) {
        int o;
        std::cin >> o;
        
        if (o == 1) {
            int i, x;
            std::cin >> i >> x;
            i--;
            seg.modify(i, Info(x, a[i]));
        } else {
            int l, r;
            std::cin >> l >> r;
            l--;
            auto res = seg.rangeQuery(l, r);
            int ans = res.ans;
            if (ans == inf) {
                ans = -1;
            }
            std::cout << ans << " ";
        }
    }
    std::cout << "\n";
}

int main() {
    std::ios::sync_with_stdio(false);
    std::cin.tie(nullptr);
    
    int t;
    std::cin >> t;
    
    while (t--) {
        solve();
    }
    
    return 0;
}

评论
成就一亿技术人!
拼手气红包6.0元
还能输入1000个字符
 
红包 添加红包
表情包 插入表情
 条评论被折叠 查看
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值